Quantum Coin Toss

An easy-to-perform quantum mechanics-based alternative to tossing a coin

import chances
import
random
# use pseudo randomness to pick either even or odd
random.choice(['even', 'odd'])
# use pseudo randomness to pick either head or tail
random.choice(['heads', 'tails'])
# set the `max` and `n` values for the random generator
rand = chances.Randomizer(1000000, 1)
# use quantum mechanical randomness to pick a number
rand.quantum()
def quantum_coin_toss(a, b):

'''Quantum coin tosser
a | str or int or list or dict | any value or set of values
b | str or int or list or dict | any value or set of values

'''

import chances
import random

# use pseudo randomness to pick either even or odd
even_or_odd = random.choice(['even', 'odd'])

# use pseudo randomness to pick either head or tail
a_or_b = random.choice([a, b])

# set the `max` and `n` values for the random generator
rand = chances.Randomizer(1000000, 1)

# use quantum mechanical randomness to pick a number
quantum_random_number = rand.quantum()[0]

# handle the case where quantum random number is even
if quantum_random_number % 2 == 0:

if even_or_odd == 'even' and a_or_b == a:
return a

elif even_or_odd == 'even' and a_or_b == b:
return b

elif even_or_odd == 'odd' and a_or_b == a:
return b

elif even_or_odd == 'odd' and a_or_b == b:
return a

if quantum_random_number % 2 != 0:

if even_or_odd == 'even' and a_or_b == a:
return b

elif even_or_odd == 'even' and a_or_b == b:
return a

elif even_or_odd == 'odd' and a_or_b == a:
return a

elif even_or_odd == 'odd' and a_or_b == b:
return b

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Mikko

Worked with machine intelligence for 15 years, and built the interwebs for 25. Nothing here is my own.